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Homework 9, due April 7, 2010.
Posted: Thu Apr 01, 2010 10:32 am
by goodwine
From the course text, 9.15, 9.16, 9.17, 9.26 and 9.30.
Re: #9.17
Posted: Sun Apr 04, 2010 9:07 pm
by cplagema
For 9.17, since the transfer function is for Xdot/F instead of X/F, does "proportional control" still refer to F=Kp*(Xdot_desired - Xdot), or now is it Kp*(X_desired - Xdot), which is really derivative control for X/F?
Thanks!
Re: #9.17
Posted: Mon Apr 05, 2010 8:40 am
by goodwine
cplagema wrote:For 9.17, since the transfer function is for Xdot/F instead of X/F, does "proportional control" still refer to F=Kp*(Xdot_desired - Xdot), or now is it Kp*(X_desired - Xdot), which is really derivative control for X/F?
Thanks!
It's the former, F=Kp*(Xdot_desired - Xdot).
Re: Homework 9, due April 7, 2010.
Posted: Mon Apr 05, 2010 10:58 am
by AL089
Professor, just a heads up but Figures 9.98 and 9.99 are pretty faded and don't show all the branches and asymptotes of the root locus, at least in my copy. It's not hard to get what the real plots look like, but it might be confusing if somebody doesn't realize that parts are missing. Again, it might only be my book.
Re: Homework 9, due April 7, 2010.
Posted: Tue Apr 06, 2010 7:15 pm
by lawnoy
Professor,
Shouldn't the expression for rise time in 9.26 be tr=1.8/wd? All the expressions of rise time in the book are in terms of damped frequency.
Re: Homework 9, due April 7, 2010.
Posted: Tue Apr 06, 2010 8:23 pm
by goodwine
lawnoy wrote:Professor,
Shouldn't the expression for rise time in 9.26 be tr=1.8/wd? All the expressions of rise time in the book are in terms of damped frequency.
No, it's the natural frequency. That's why I specified it in the problem.