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Homework 6, due October 10, 2016.
Posted: Tue Oct 04, 2016 1:16 pm
by goodwine
Reading: Chapter 4.
Exercises: 4.14, 4.17, 4.19 and 4.29.
For 4.14, also indicate how the solution would change if
- the rotational speed of the rollers is increased
- the coefficient of friction is increased
- the density of the board is increased and
- the length of the board is increased.
Re: Homework 6, due October 10, 2016.
Posted: Sat Oct 08, 2016 11:53 am
by garrett_schwartz
For problem 4.19 part 4, should we assume the initial value of b, or a decreased value?
Re: Homework 6, due October 10, 2016.
Posted: Sat Oct 08, 2016 12:58 pm
by goodwine
garrett_schwartz wrote:For problem 4.19 part 4, should we assume the initial value of b, or a decreased value?
Use the initial value of b.
Re: Homework 6, due October 10, 2016.
Posted: Sat Oct 08, 2016 4:21 pm
by kgilhoo1
For 4.19:
to solve for wn I did sqrt(k) and got 94.87
-> for zeta I did b/2*wn... this leaves me with z=12.65
I'm not sure how to correlate this z to the Fig 4.20 because the highest z value is 1. I may have just completely solved for z incorrectly
Re: Homework 6, due October 10, 2016.
Posted: Sat Oct 08, 2016 6:16 pm
by goodwine
kgilhoo1 wrote:For 4.19:
to solve for wn I did sqrt(k) and got 94.87
-> for zeta I did b/2*wn... this leaves me with z=12.65
I'm not sure how to correlate this z to the Fig 4.20 because the highest z value is 1. I may have just completely solved for z incorrectly
The natural frequency is sqrt(k/m) so should be 3. With that your zeta should be in the right range.
Re: Homework 6, due October 10, 2016.
Posted: Sat Oct 08, 2016 7:22 pm
by kgilhoo1
Thank you!
Re: Homework 6, due October 10, 2016.
Posted: Sun Oct 09, 2016 10:45 am
by ccunnin6
For question 4.29, is the equation x'' + 1/(5x') +... or x'' + (1/5)x' +...?
Re: Homework 6, due October 10, 2016.
Posted: Sun Oct 09, 2016 1:28 pm
by goodwine
ccunnin6 wrote:For question 4.29, is the equation x'' + 1/(5x') +... or x'' + (1/5)x' +...?
The latter. The former would be nonlinear and also would not make any sense for vibrations.