Homework 9, due April 7, 2010.
-
- Site Admin
- Posts: 1596
- Joined: Tue Aug 24, 2004 4:54 pm
- Location: 376 Fitzpatrick
- Contact:
Homework 9, due April 7, 2010.
From the course text, 9.15, 9.16, 9.17, 9.26 and 9.30.
Bill Goodwine, 376 Fitzpatrick
-
- Site Admin
- Posts: 1596
- Joined: Tue Aug 24, 2004 4:54 pm
- Location: 376 Fitzpatrick
- Contact:
Re: #9.17
It's the former, F=Kp*(Xdot_desired - Xdot).cplagema wrote:For 9.17, since the transfer function is for Xdot/F instead of X/F, does "proportional control" still refer to F=Kp*(Xdot_desired - Xdot), or now is it Kp*(X_desired - Xdot), which is really derivative control for X/F?
Thanks!
Bill Goodwine, 376 Fitzpatrick
Re: Homework 9, due April 7, 2010.
Professor, just a heads up but Figures 9.98 and 9.99 are pretty faded and don't show all the branches and asymptotes of the root locus, at least in my copy. It's not hard to get what the real plots look like, but it might be confusing if somebody doesn't realize that parts are missing. Again, it might only be my book.
Re: Homework 9, due April 7, 2010.
Professor,
Shouldn't the expression for rise time in 9.26 be tr=1.8/wd? All the expressions of rise time in the book are in terms of damped frequency.
Shouldn't the expression for rise time in 9.26 be tr=1.8/wd? All the expressions of rise time in the book are in terms of damped frequency.
-
- Site Admin
- Posts: 1596
- Joined: Tue Aug 24, 2004 4:54 pm
- Location: 376 Fitzpatrick
- Contact:
Re: Homework 9, due April 7, 2010.
No, it's the natural frequency. That's why I specified it in the problem.lawnoy wrote:Professor,
Shouldn't the expression for rise time in 9.26 be tr=1.8/wd? All the expressions of rise time in the book are in terms of damped frequency.
Bill Goodwine, 376 Fitzpatrick