Homework 9, due April 7, 2010.

Due Wednesday, April 7, 2010.
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goodwine
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Homework 9, due April 7, 2010.

Post by goodwine »

From the course text, 9.15, 9.16, 9.17, 9.26 and 9.30.
Bill Goodwine, 376 Fitzpatrick
cplagema

Re: #9.17

Post by cplagema »

For 9.17, since the transfer function is for Xdot/F instead of X/F, does "proportional control" still refer to F=Kp*(Xdot_desired - Xdot), or now is it Kp*(X_desired - Xdot), which is really derivative control for X/F?
Thanks!
goodwine
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Re: #9.17

Post by goodwine »

cplagema wrote:For 9.17, since the transfer function is for Xdot/F instead of X/F, does "proportional control" still refer to F=Kp*(Xdot_desired - Xdot), or now is it Kp*(X_desired - Xdot), which is really derivative control for X/F?
Thanks!
It's the former, F=Kp*(Xdot_desired - Xdot).
Bill Goodwine, 376 Fitzpatrick
AL089

Re: Homework 9, due April 7, 2010.

Post by AL089 »

Professor, just a heads up but Figures 9.98 and 9.99 are pretty faded and don't show all the branches and asymptotes of the root locus, at least in my copy. It's not hard to get what the real plots look like, but it might be confusing if somebody doesn't realize that parts are missing. Again, it might only be my book.
lawnoy

Re: Homework 9, due April 7, 2010.

Post by lawnoy »

Professor,

Shouldn't the expression for rise time in 9.26 be tr=1.8/wd? All the expressions of rise time in the book are in terms of damped frequency.
goodwine
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Re: Homework 9, due April 7, 2010.

Post by goodwine »

lawnoy wrote:Professor,

Shouldn't the expression for rise time in 9.26 be tr=1.8/wd? All the expressions of rise time in the book are in terms of damped frequency.
No, it's the natural frequency. That's why I specified it in the problem.
Bill Goodwine, 376 Fitzpatrick
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