P. 185, line 2: Difference between revisions

Latest revision as of 20:09, 2 November 2011

The equation should be

$a_{n + 2} = \frac{(n - λ) (n + λ)}{(n + 1) (n + 2)} a_{n}$ .

Revision as of 20:28, 28 October 2011 view source Goodwine (talk \| contribs) 1,319 edits Created page with "The equation should be <math>a_{n+2} = \frac{(n-\lambda)(n+\lambda)}{(n+1)(n+2)}a_n</math>."		Latest revision as of 20:09, 2 November 2011 view source Goodwine (talk \| contribs) 1,319 edits No edit summary
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	<math>a_{n+2} = \frac{(n-\lambda)(n+\lambda)}{(n+1)(n+2)}a_n</math>.		<math>a_{n+2} = \frac{(n-\lambda)(n+\lambda)}{(n+1)(n+2)}a_n</math>.

			[[Engineering Differential Equations: Theory and Applications, Springer 2010#Errata\|Return to errata.]]