P. 244, line -11: Difference between revisions
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<math>\int_0^t \Xi^{-1}(\tau)g(\tau) d \tau =</math> | <math>\int_0^t \Xi^{-1}(\tau)g(\tau) d \tau = \int_0^t \left[ \begin{array}{c} -\frac{1}{2} \\ \frac{1}{2} e^{-2 \tau} \end{array} \right]</math> | ||
Revision as of 15:00, 25 January 2011
The line should be
![{\displaystyle \int _{0}^{t}\Xi ^{-1}(\tau )g(\tau )d\tau =\int _{0}^{t}\left[{\begin{array}{c}-{\frac {1}{2}}\\{\frac {1}{2}}e^{-2\tau }\end{array}}\right]}](https://wikimedia.org/api/rest_v1/media/math/render/svg/a050a30ae9a048aeda984e45e8a50e6a362fe2b0)
