Difference between revisions of "P. 186, line 6"

Latest revision as of 16:09, 2 November 2011

The equation should be

$a_{n+2}=-{\frac {(\lambda -n)(\lambda +n+1)}{(n+1)(n+2)}}a_{n}$ .

Revision as of 16:45, 28 October 2011 (view source) Goodwine (talk \| contribs) ← Older edit		Latest revision as of 16:09, 2 November 2011 (view source) Goodwine (talk \| contribs)
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	<math>a_{n+2} = -\frac{(\lambda - n)(\lambda + n + 1)}{(n+1)(n+2)}a_n</math>.		<math>a_{n+2} = -\frac{(\lambda - n)(\lambda + n + 1)}{(n+1)(n+2)}a_n</math>.
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		+	[[Engineering Differential Equations: Theory and Applications, Springer 2010#Errata\|Return to errata.]]