University of Notre Dame
Aerospace and Mechanical Engineering

AME 30314: Differential Equations, Vibrations and Controls I
Fall 2015
Homework 3


Problem 1
Determine whether each of the given functions, $ x(t)$ is a solution to the associated differential equation.
  1. $ x(t) = \sin(t), \ddot{x} + x = 0$ .
  2. $ x(t) = \cos(2 t), \ddot{x} + x = 0$ .
  3. $ x(t) = 3 t + 2 / t , t^2 \ddot{x} + t \dot{x} - x = 0 , t \neq 0$ .
  4. $ x(t) = \cos(2 t) , x^2 \ddot{x} + \dot{x} / x = - 4 \cos^3 (2 t) - 2 \tan(2 t)$ .
  5. $ x(t) = t + 1/t + 5 t / 2 \ln(t) , t^2 \ddot{x} + t \dot{x} - x = t , t \neq 0$ .

Problem 2
Consider a uniform flexible rope of length $ l$ and total mass $ \rho l$ , as is illustrated on the right in Figure 1. Assume that the length of rope hanging off the end of the table is $ x$ and that the coefficient of friction (both dynamic and static) between the rope and table is $ \mu$ . Determine a differential equation with dependent variable $ x$ and independent variable $ t$ that describes the motion of the rope. What are the units for each term in the equation?

Figure: System for Problem 2
Image hw03-prob02

Problem 3
Based on Theorem D.1 in the textbook 1, which of the following differential equations are guaranteed to have solutions that exist and are unique?

  1. $ \dot x = x$ where $ x(0) = 0$ .
  2. $ \dot x^2 = x$ where $ x(0) = 0$ .
  3. $ \dot x = \begin{cases}-1, & x \geq 0, \\
1, & x < 0,
\end{cases}$
    where $ x(0) = 0$ .
  4. $ \dot x = \begin{cases}-1, & t \geq 5, \\
1, & t < 5,
\end{cases}$
    where $ x(0) = 0$ .
  5. $ \dot x = x^2$ where $ x(0) = 0$ .
  6. $ \dot x = x^{1/2}$ where $ x(0) = 0$ .
  7. $ \dot x = -\left\vert x\right\vert$ where $ x(0) = 0$ .
  8. $ \dot x = \sqrt{x^2 + 9}$ where $ x(0) = 0$ .

Problem 4
Show that the set of functions $ \left\{t^0, t^1, t^2, t^3, t^4,
\ldots, t^n \right\}$ is linearly independent.

Problem 5
Show that

$\displaystyle \left( 2 t^2 + 3 x \sin^2 t\right) \frac{d x}{d t} + 2x \left( t + x \sin t \cos t\right) = 0
$

is not exact, but when multiplied by $ \mu(x,t) = x$ , it is exact. Find the solution. Leaving the solution in implicit form is fine.

Problem 6
One special case where it is possible to determine an integrating factor is when it only depends on $ t$ . In such a case, the equation:

$\displaystyle f(x,t)\frac{\partial \mu}{\partial t}(x,t)+
\mu(x,t)\frac{\partia...
...{\partial \mu}{\partial t}(x,t)-
\mu(x,t)\frac{\partial g}{\partial t}(x,t)= 0
$

reduces to

$\displaystyle f(x,t) \frac{d \mu}{d t}(t) +
\mu(t)\frac{\partial f}{\partial t}(x,t) -
\mu(t)\frac{\partial g}{\partial x}(x,t) =0
$

which gives

$\displaystyle \frac{1}{\mu(t)}\frac{d \mu}{d t}(t) = \frac{\frac{\partial g}{\partial x}(x,t) - \frac{\partial f}{\partial t}(x,t)}{f(x,t)}.$ (1)

  1. Show that if we additionally have that the right-hand side of Equation ([*]) is only a function of $ t$ , then $ \mu(t)$ is given by

    $\displaystyle \mu(t) = \exp \! \left(\int \frac{\frac{\partial g}{\partial x}(x) - \frac{\partial f}{\partial t}(x)}{f(x)} d x \right).
$

  2. Show that $ \left(e^t - \sin x \right) + \cos x(d x/d t) = 0$ is not exact, but that the above method to determine an integrating factor applies. Use that to find the solution.



2015-09-11